The function Split.all seems to be ignoring a basic convention of CSV formatting? My text.readln command reads a csv header row thus:- Number,Scheme,Location,Date,Category,"L-Lost, R-Repaired, D-Discarded",Serviced
When I then use Split.all with the comma delimiter and print I get:- Number Scheme Location Category "L-Lost R-Repaired D-Discarded" Serviced
The convention of processing values between delimiters is to treat a value enclosed in quotes ("...") as an entire value. Is there a way to use the regular-expression facility of the delimiter parameter to get:-
Number Scheme Location Category L-Lost, R-Repaired, D-Discarded Serviced
Last edited by chrisRoald on Sat Dec 03, 2016 4:36 am, edited 2 times in total.
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