Fri May 19, 2017 1:36 pm

Suppose we know the following information about two colliding circular objects:

Mass of both objects

X velocity of both objects

y velocity of both objects

Is there a formula to compute the new x and y velocities of each object?

Mass of both objects

X velocity of both objects

y velocity of both objects

Is there a formula to compute the new x and y velocities of each object?

Fri May 19, 2017 5:39 pm

Yes

https://en.wikipedia.org/wiki/Momentum

You can also use the German article with more details for your case.

The result of Google Translate to English is acceptable.

[url]https://de.wikipedia.org/wiki/Stoß_(Physik)[/url]

Gregor

https://en.wikipedia.org/wiki/Momentum

You can also use the German article with more details for your case.

The result of Google Translate to English is acceptable.

[url]https://de.wikipedia.org/wiki/Stoß_(Physik)[/url]

Gregor

Sat May 20, 2017 2:54 am

lladutke wrote:Suppose we know the following information about two colliding circular objects:

Mass of both objects

X velocity of both objects

y velocity of both objects

Is there a formula to compute the new x and y velocities of each object?

Are these 2D objects in flatworld that nevertheless have mass? In the real world what happens depends on whether the objects are purely elastic and no energy or momentum is lost. If they stuck together, for instance, the result would be different!

But I must go and read Gregor's more useful answer...

Mike.

Sat May 20, 2017 5:09 am

They are represented as 2D circles, but for the purposes of collisions, I wanted to assume that each circle has a mass equivalent to the volume of a sphere with density being held constant. mass = 4/3 * pi() * radius^3 * density (density = 1)

Sat May 20, 2017 9:11 am

Here a step-by-step recipe, based on vector-calculations:

https://www.google.de/url?sa=t&source=web&rct=j&url=http://vobarian.com/collisions/2dcollisions2.pdf&ved=0ahUKEwjW0MGj7f7TAhVNlxQKHRMUAEcQFggeMAE&usg=AFQjCNH00E1a9fjTcSjSG3o9CbYJIu5dOg&sig2=Amkh9VGTFzm_KjTMrjfBzg

...but think it is not the fastest!

brochi

https://www.google.de/url?sa=t&source=web&rct=j&url=http://vobarian.com/collisions/2dcollisions2.pdf&ved=0ahUKEwjW0MGj7f7TAhVNlxQKHRMUAEcQFggeMAE&usg=AFQjCNH00E1a9fjTcSjSG3o9CbYJIu5dOg&sig2=Amkh9VGTFzm_KjTMrjfBzg

...but think it is not the fastest!

brochi